Archiv für den Monat: Juni 2018

Allgemein

BWIN.COM & Mobile/Handy: Wie bekomme ich das Geld zurück auf mein Paypal-Konto bei bwin.com (bet and win) / How-to get your money back to your Paypal-Account ( VISA / Neteller / Fast Bank Transfer / Skrill )

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Problem

Sie wissen nicht wie Sie per Handy ihr (vorhandenes) Geld auf dem BWIN-Konto zurück per Paypal bekommen?
You do not know where to find the option in the mobile version to get back your money on bwin.com (bet and win) ?

Solution – Lösung

Öffnen Sie bwin.com auf ihrem Mobiltelefon und loggen sie sich ein
In der oberen linken Ecke klicken sie auf das Menü-Symbol
In dem erscheinenden Menü wählen sie die Option „Cashier“
Die gewünschte Option heißt „Withdrawal“, welche Sie nun per Klick auswählen
Nun können sie ihre bevorzugte Geld-zurück-Weise wählen (z.B. Paypal)
Geben Sie den Betrag ein, den Sie zurückbuchen möchten
Geben Sie weitere Daten, die für ihre gewählte Zahlungsweise nötig sind, an.

Open bwin.com on your mobile phone and log-in
Click the upper left corner (menu button) on the mobile version of the website.
In the appearing menu select „Cashier“
Click the „Withdrawal“ Option
You can select VISA / Neteller / PayPal / Fast Bank Transfer / Skrill
Choose the amount you want to get back from you bwin-account
Enter additional data according to your payment method

Access, Datenbanken, MS SQL Server, Sparx Systems Enterprise Architect, SQL

Sparx Systems Enterprise Architect: Get Images of Diagram By Diagram Name SQL

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Problem

The Images of a specific diagram in the data structure of the Sparx Systems Enterprise Architect should be read by diagram name.

Approach

Usage of MDB Plus and Data Mining

Solution

This is SQL for the Access / .eap-File – it should be rewritten for other SQL Servers (i.e. the brackets can be removed and Functions like InStr/Mid shall be replaced)

SELECT	dia.Name As Diagram,
		IIF(Trim(objstart.[Name]) = 'Text', 'Text', objstart.stereotype) As stereotype, 
		diaobj.RectLeft As x,
		diaobj.RectTop As y,
		diaobj.RectRight-diaobj.RectLeft As Width,
		Abs(diaobj.RectBottom-diaobj.RectTop) As Height,
		objstart.Object_ID,
		IIF(Trim(objstart.[Name]) = 'Text', 'Text-'& objstart.Object_ID ,objstart.Alias) As [key],
		IIF(objstart.[Name] = 'Text', objstart.Note, objstart.[Name]) As phaseName,
		objstart.[ea_guid] As [guid],
		diaobj.ObjectStyle,
		IIF(
                    InStr(diaobj.ObjectStyle, "ImageID")>0, 
                    Mid(diaobj.ObjectStyle, InStr(diaobj.ObjectStyle, "ImageID")+8 , Len(diaobj.ObjectStyle)- (InStr( diaobj.ObjectStyle, "ImageID")+8) ),
                    ''
        ) As ImageId     
FROM
((
		[t_diagram] dia LEFT JOIN (Select Diagram_ID, Object_ID, RectLeft, RectTop, RectRight, RectBottom, ObjectStyle from [t_diagramobjects]) diaobj ON dia.[Diagram_ID]=diaobj.[Diagram_ID])
LEFT JOIN [t_object] objstart ON objstart.[Object_ID]=diaobj.[Object_ID])
WHERE objstart.Object_Type IN ('Text','Boundary') AND IIF(InStr(diaobj.ObjectStyle, "ImageID")>0, 
                                                                Mid(diaobj.ObjectStyle, InStr(diaobj.ObjectStyle, "ImageID")+8 , 
                                                                Len(diaobj.ObjectStyle)- (InStr( diaobj.ObjectStyle, "ImageID")+8) ),
                                                                '') <> ''
AND dia.Name='0' 
ORDER BY 12 DESC,1,2,3,4,5,6,7,8,9
Sparx Systems Enterprise Architect, SQL

Sparx Systems Enterprise Architect SQL: Get all Images with ImageID of a diagram

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Problem

All Images of an Diagram (the ImageIds) shall be determined, so that can be read out from the table t_image (see previous article about BLOB and EA).

Approach – Ansatz

Usage of the tables
– t_diagram
– t_diagramobjects
– t_object

Solution – Lösung

SELECT	dia.Name As Diagram,
		IIF(Trim(objstart.[Name]) = 'Text', 'Text', objstart.stereotype) As stereotype, 
		diaobj.RectLeft As x,
		diaobj.RectTop As y,
		diaobj.RectRight-diaobj.RectLeft As Width,
		Abs(diaobj.RectBottom-diaobj.RectTop) As Height,
		objstart.Object_ID,
		IIF(Trim(objstart.[Name]) = 'Text', 'Text-'& objstart.Object_ID ,objstart.Alias) As [key],
		IIF(objstart.[Name] = 'Text', objstart.Note, objstart.[Name]) As phaseName,
		objstart.[ea_guid] As [guid],
		diaobj.ObjectStyle,
		IIF(
                    InStr(diaobj.ObjectStyle, "ImageID")>0, 
                    Mid(diaobj.ObjectStyle, InStr(diaobj.ObjectStyle, "ImageID")+8 , Len(diaobj.ObjectStyle)- (InStr( diaobj.ObjectStyle, "ImageID")+8) ),
                    ''
        ) As ImageId     
FROM
((
		[t_diagram] dia LEFT JOIN (Select Diagram_ID, Object_ID, RectLeft, RectTop, RectRight, RectBottom, ObjectStyle from [t_diagramobjects]) diaobj ON dia.[Diagram_ID]=diaobj.[Diagram_ID])
LEFT JOIN [t_object] objstart ON objstart.[Object_ID]=diaobj.[Object_ID])
WHERE objstart.Object_Type IN ('Text','Boundary') AND IIF(InStr(diaobj.ObjectStyle, "ImageID")>0, 
                                                                Mid(diaobj.ObjectStyle, InStr(diaobj.ObjectStyle, "ImageID")+8 , 
                                                                Len(diaobj.ObjectStyle)- (InStr( diaobj.ObjectStyle, "ImageID")+8) ),
                                                                '') <> ''
AND dia.Name='{PutInYourDiagramNameHere}' 
ORDER BY 12 DESC,1,2,3,4,5,6,7,8,9
Access, Datenbanken, MS SQL Server, Sparx Systems Enterprise Architect, SQL

Sparx Systems Enterprise Architect SQL : Query to get the order of objects / elements in the project browser tree

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Problem

The order of tree elements in the project browser should be queried in SQL.
Die Reihenfolge der Objekte im Projekt-Browser soll über SQL abgefragt werden

Approach – Ansatz

Usage of the TPos column within the tables t_object and t_package.
Verwendung der TPos Spalte in den Tabellen t_object und t_package.

Solution – Lösung

SELECT b.TPos as Package_Position, 
       b.Name as Package_Name, 
       a.TPos as Object_Tree_Position, 
       a.Object_ID, 
       a.Name as Object_Description
FROM t_object a INNER JOIN t_package b ON a.Package_ID=b.Package_ID 
WHERE Stereotype='Process Step'
ORDER BY 1,2,3